For the PN order described as 2400 mL with 300 grams dextrose and 90 grams protein plus 225 mL of 20% IVFE, what is the total caloric content, protein, fat, and final volume?

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Multiple Choice

For the PN order described as 2400 mL with 300 grams dextrose and 90 grams protein plus 225 mL of 20% IVFE, what is the total caloric content, protein, fat, and final volume?

Explanation:
Calculating PN content uses standard energy densities for each component: carbohydrate provides about 3.4 kcal per gram, protein 4 kcal per gram, and fat in PN emulsions delivers about 10 kcal per gram. The fat in the IVFE is found from the volume and percent fat: 225 mL × 0.20 = 45 g fat, which yields 450 kcal (45 g × 10 kcal/g). The dextrose 300 g contributes 300 × 3.4 = 1020 kcal. Protein at 90 g provides 90 × 4 = 360 kcal. Add them: 1020 + 360 + 450 = 1830 kcal. The final volume is the base PN volume plus the IVFE volume: 2400 mL + 225 mL = 2625 mL. So you get 1830 kcal, 90 g protein, 45 g fat, and 2625 mL.

Calculating PN content uses standard energy densities for each component: carbohydrate provides about 3.4 kcal per gram, protein 4 kcal per gram, and fat in PN emulsions delivers about 10 kcal per gram. The fat in the IVFE is found from the volume and percent fat: 225 mL × 0.20 = 45 g fat, which yields 450 kcal (45 g × 10 kcal/g). The dextrose 300 g contributes 300 × 3.4 = 1020 kcal. Protein at 90 g provides 90 × 4 = 360 kcal. Add them: 1020 + 360 + 450 = 1830 kcal. The final volume is the base PN volume plus the IVFE volume: 2400 mL + 225 mL = 2625 mL. So you get 1830 kcal, 90 g protein, 45 g fat, and 2625 mL.

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